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(x+6)(2x+-1)=0
We add all the numbers together, and all the variables
(x+6)(2x-1)=0
We multiply parentheses ..
(+2x^2-1x+12x-6)=0
We get rid of parentheses
2x^2-1x+12x-6=0
We add all the numbers together, and all the variables
2x^2+11x-6=0
a = 2; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·2·(-6)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-13}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+13}{2*2}=\frac{2}{4} =1/2 $
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