12(x+2)=8(13-x)

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Solution for 12(x+2)=8(13-x) equation: 



12(x+2)=8(13-x)

We move all terms to the left:

12(x+2)-(8(13-x))=0

We add all the numbers together, and all the variables

12(x+2)-(8(-1x+13))=0

We multiply parentheses

12x-(8(-1x+13))+24=0



We calculate terms in parentheses: -(8(-1x+13)), so:

8(-1x+13)

We multiply parentheses

-8x+104

Back to the equation:

-(-8x+104)



We get rid of parentheses

12x+8x-104+24=0

We add all the numbers together, and all the variables

20x-80=0

We move all terms containing x to the left, all other terms to the right

20x=80

x=80/20

x=4

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