X(2x-7)(3x+1)=(2x-5)(3x+2)

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Solution for X(2x-7)(3x+1)=(2x-5)(3x+2) equation:



X(2X-7)(3X+1)=(2X-5)(3X+2)
We move all terms to the left:
X(2X-7)(3X+1)-((2X-5)(3X+2))=0
We multiply parentheses ..
X(+6X^2+2X-21X-7)-((2X-5)(3X+2))=0
We calculate terms in parentheses: -((2X-5)(3X+2)), so:
(2X-5)(3X+2)
We multiply parentheses ..
(+6X^2+4X-15X-10)
We get rid of parentheses
6X^2+4X-15X-10
We add all the numbers together, and all the variables
6X^2-11X-10
Back to the equation:
-(6X^2-11X-10)
We multiply parentheses
6X^3+2X^2-21X^2-7X-(6X^2-11X-10)=0
We get rid of parentheses
6X^3+2X^2-21X^2-6X^2-7X+11X+10=0
We do not support eXpression: X^3

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