(x+52)=(10x-38)

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Solution for (x+52)=(10x-38) equation: 



(x+52)=(10x-38)

We move all terms to the left:

(x+52)-((10x-38))=0

We get rid of parentheses

x-((10x-38))+52=0



We calculate terms in parentheses: -((10x-38)), so:

(10x-38)

We get rid of parentheses

10x-38

Back to the equation:

-(10x-38)



We get rid of parentheses

x-10x+38+52=0

We add all the numbers together, and all the variables

-9x+90=0

We move all terms containing x to the left, all other terms to the right

-9x=-90

x=-90/-9

x=+10

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