(x+4)-2(3-2x)=2(x+4)-4

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Solution for (x+4)-2(3-2x)=2(x+4)-4 equation: 



(x+4)-2(3-2x)=2(x+4)-4

We move all terms to the left:

(x+4)-2(3-2x)-(2(x+4)-4)=0

We add all the numbers together, and all the variables

(x+4)-2(-2x+3)-(2(x+4)-4)=0

We multiply parentheses

(x+4)+4x-(2(x+4)-4)-6=0

We get rid of parentheses

x+4x-(2(x+4)-4)+4-6=0



We calculate terms in parentheses: -(2(x+4)-4), so:

2(x+4)-4

We multiply parentheses

2x+8-4

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

5x-(2x+4)-2=0

We get rid of parentheses

5x-2x-4-2=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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