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(2x-8)-1/2(9-4x)+5/2=x
We move all terms to the left:
(2x-8)-1/2(9-4x)+5/2-(x)=0
Domain of the equation: 2(9-4x)!=0We add all the numbers together, and all the variables
x∈R
(2x-8)-1/2(-4x+9)-x+5/2=0
We add all the numbers together, and all the variables
-1x+(2x-8)-1/2(-4x+9)+5/2=0
We get rid of parentheses
-1x+2x-1/2(-4x+9)-8+5/2=0
We calculate fractions
-1x+2x-8=0
We add all the numbers together, and all the variables
x-8=0
We move all terms containing x to the left, all other terms to the right
x=8
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