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2/5h-7=12/5h+3
We move all terms to the left:
2/5h-7-(12/5h+3)=0
Domain of the equation: 5h!=0
h!=0/5
h!=0
h∈R
Domain of the equation: 5h+3)!=0We get rid of parentheses
h∈R
2/5h-12/5h-3-7=0
We multiply all the terms by the denominator
-3*5h-7*5h+2-12=0
We add all the numbers together, and all the variables
-3*5h-7*5h-10=0
Wy multiply elements
-15h-35h-10=0
We add all the numbers together, and all the variables
-50h-10=0
We move all terms containing h to the left, all other terms to the right
-50h=10
h=10/-50
h=-1/5
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