(x+3)(x+4)=(x+1)(x+2

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Solution for (x+3)(x+4)=(x+1)(x+2 equation: 



(x+3)(x+4)=(x+1)(x+2

We move all terms to the left:

(x+3)(x+4)-((x+1)(x+2)=0

We multiply parentheses ..

(+x^2+4x+3x+12)-((x+1)(x+2)=0



We calculate terms in parentheses: -((x+1)(x+2), so:

(x+1)(x+2



We get rid of parentheses

x^2+4x+3x-((x+1)(x+2)+12=0

We multiply parentheses ..

x^2-((+x^2+2x+x+2)+12+4x+3x=0

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