5(2.2y+3.4)=5(1y-2)+6y

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Solution for 5(2.2y+3.4)=5(1y-2)+6y equation: 



5(2.2y+3.4)=5(1y-2)+6y

We move all terms to the left:

5(2.2y+3.4)-(5(1y-2)+6y)=0

We add all the numbers together, and all the variables

5(2.2y+3.4)-(5(y-2)+6y)=0

We multiply parentheses

10y-(5(y-2)+6y)+17=0



We calculate terms in parentheses: -(5(y-2)+6y), so:

5(y-2)+6y

We add all the numbers together, and all the variables

6y+5(y-2)

We multiply parentheses

6y+5y-10

We add all the numbers together, and all the variables

11y-10

Back to the equation:

-(11y-10)



We get rid of parentheses

10y-11y+10+17=0

We add all the numbers together, and all the variables

-1y+27=0

We move all terms containing y to the left, all other terms to the right

-y=-27

y=-27/-1

y=+27

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