8z-22=3(3z2+11)-z

Solution for 8z-22=3(3z2+11)-z equation:

8z-22=3(3z^2+11)-z

We move all terms to the left:

8z-22-(3(3z^2+11)-z)=0


We calculate terms in parentheses: -(3(3z^2+11)-z), so:

3(3z^2+11)-z

We add all the numbers together, and all the variables

-1z+3(3z^2+11)

We multiply parentheses

9z^2-1z+33

Back to the equation:

-(9z^2-1z+33)


We get rid of parentheses

-9z^2+8z+1z-33-22=0

We add all the numbers together, and all the variables

-9z^2+9z-55=0

a = -9; b = 9; c = -55;
Δ = b2-4ac
Δ = 92-4·(-9)·(-55)
Δ = -1899
Delta is less than zero, so there is no solution for the equation