(x+24)(x-2)=0

Solution for (x+24)(x-2)=0 equation:

(x+24)(x-2)=0

We multiply parentheses ..

(+x^2-2x+24x-48)=0

We get rid of parentheses

x^2-2x+24x-48=0

We add all the numbers together, and all the variables

x^2+22x-48=0

a = 1; b = 22; c = -48;
Δ = b2-4ac
Δ = 222-4·1·(-48)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-26}{2*1}=\frac{-48}{2}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+26}{2*1}=\frac{4}{2}
=2
$