4+2c=3(c-2)+1

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Solution for 4+2c=3(c-2)+1 equation: 



4+2c=3(c-2)+1

We move all terms to the left:

4+2c-(3(c-2)+1)=0



We calculate terms in parentheses: -(3(c-2)+1), so:

3(c-2)+1

We multiply parentheses

3c-6+1

We add all the numbers together, and all the variables

3c-5

Back to the equation:

-(3c-5)



We get rid of parentheses

2c-3c+5+4=0

We add all the numbers together, and all the variables

-1c+9=0

We move all terms containing c to the left, all other terms to the right

-c=-9

c=-9/-1

c=+9

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