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(x+2)=(x-3)
We move all terms to the left:
(x+2)-((x-3))=0
We get rid of parentheses
x-((x-3))+2=0
We calculate terms in parentheses: -((x-3)), so:We get rid of parentheses
(x-3)
We get rid of parentheses
x-3
Back to the equation:
-(x-3)
x-x+3+2=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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