(20-3y)/4=(7-y)/2

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Solution for (20-3y)/4=(7-y)/2 equation: 



(20-3y)/4=(7-y)/2

We move all terms to the left:

(20-3y)/4-((7-y)/2)=0

We add all the numbers together, and all the variables

(-3y+20)/4-((-1y+7)/2)=0

We calculate fractions


(-3y)/()+(-((-1y+7)*4)/()=0



We calculate terms in parentheses: +(-((-1y+7)*4)/(), so:

-((-1y+7)*4)/(

We multiply all the terms by the denominator


-((-1y+7)*4)



We calculate terms in parentheses: -((-1y+7)*4), so:

(-1y+7)*4

We multiply parentheses

-4y+28

Back to the equation:

-(-4y+28)



We get rid of parentheses

4y-28

Back to the equation:

+(4y-28)



We get rid of parentheses

(-3y)/()+4y-28=0

We multiply all the terms by the denominator


(-3y)+4y*()-28*()=0

We add all the numbers together, and all the variables

(-3y)+4y*()=0

We get rid of parentheses

-3y+4y*()=0

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