4(2x-8)-5=4(x-3)+11

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Solution for 4(2x-8)-5=4(x-3)+11 equation: 



4(2x-8)-5=4(x-3)+11

We move all terms to the left:

4(2x-8)-5-(4(x-3)+11)=0

We multiply parentheses

8x-(4(x-3)+11)-32-5=0



We calculate terms in parentheses: -(4(x-3)+11), so:

4(x-3)+11

We multiply parentheses

4x-12+11

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

8x-(4x-1)-37=0

We get rid of parentheses

8x-4x+1-37=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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