(x+2)(x+3)(x+4)=48

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Solution for (x+2)(x+3)(x+4)=48 equation: 



(x+2)(x+3)(x+4)=48

We move all terms to the left:

(x+2)(x+3)(x+4)-(48)=0

We multiply parentheses ..

(+x^2+3x+2x+6)(x+4)-48=0

We move all terms containing x to the left, all other terms to the right

(+x^2+3x+2x+6)(x+4)=48

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