7x-5+2x=4(2x+4)-(3x-4)

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Solution for 7x-5+2x=4(2x+4)-(3x-4) equation: 



7x-5+2x=4(2x+4)-(3x-4)

We move all terms to the left:

7x-5+2x-(4(2x+4)-(3x-4))=0

We add all the numbers together, and all the variables

9x-(4(2x+4)-(3x-4))-5=0



We calculate terms in parentheses: -(4(2x+4)-(3x-4)), so:

4(2x+4)-(3x-4)

We multiply parentheses

8x-(3x-4)+16

We get rid of parentheses

8x-3x+4+16

We add all the numbers together, and all the variables

5x+20

Back to the equation:

-(5x+20)



We get rid of parentheses

9x-5x-20-5=0

We add all the numbers together, and all the variables

4x-25=0

We move all terms containing x to the left, all other terms to the right

4x=25

x=25/4

x=6+1/4

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