3(2x-5)+4x=6(x+2)+1

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Solution for 3(2x-5)+4x=6(x+2)+1 equation: 



3(2x-5)+4x=6(x+2)+1

We move all terms to the left:

3(2x-5)+4x-(6(x+2)+1)=0

We add all the numbers together, and all the variables

4x+3(2x-5)-(6(x+2)+1)=0

We multiply parentheses

4x+6x-(6(x+2)+1)-15=0



We calculate terms in parentheses: -(6(x+2)+1), so:

6(x+2)+1

We multiply parentheses

6x+12+1

We add all the numbers together, and all the variables

6x+13

Back to the equation:

-(6x+13)



We add all the numbers together, and all the variables

10x-(6x+13)-15=0

We get rid of parentheses

10x-6x-13-15=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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