(x+2)(3x-4)=(x+5)(2x-5)

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Solution for (x+2)(3x-4)=(x+5)(2x-5) equation: 



(x+2)(3x-4)=(x+5)(2x-5)

We move all terms to the left:

(x+2)(3x-4)-((x+5)(2x-5))=0

We multiply parentheses ..

(+3x^2-4x+6x-8)-((x+5)(2x-5))=0



We calculate terms in parentheses: -((x+5)(2x-5)), so:

(x+5)(2x-5)

We multiply parentheses ..

(+2x^2-5x+10x-25)

We get rid of parentheses

2x^2-5x+10x-25

We add all the numbers together, and all the variables

2x^2+5x-25

Back to the equation:

-(2x^2+5x-25)



We get rid of parentheses

3x^2-2x^2-4x+6x-5x-8+25=0

We add all the numbers together, and all the variables

x^2-3x+17=0

a = 1; b = -3; c = +17;
Δ = b2-4ac
Δ = -32-4·1·17
Δ = -59
Delta is less than zero, so there is no solution for the equation

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