2(n+3)=3(n+1)

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Solution for 2(n+3)=3(n+1) equation: 



2(n+3)=3(n+1)

We move all terms to the left:

2(n+3)-(3(n+1))=0

We multiply parentheses

2n-(3(n+1))+6=0



We calculate terms in parentheses: -(3(n+1)), so:

3(n+1)

We multiply parentheses

3n+3

Back to the equation:

-(3n+3)



We get rid of parentheses

2n-3n-3+6=0

We add all the numbers together, and all the variables

-1n+3=0

We move all terms containing n to the left, all other terms to the right

-n=-3

n=-3/-1

n=+3

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