2(x+3)+3(x-1)+13=4(x+5)+19

Solution for 2(x+3)+3(x-1)+13=4(x+5)+19 equation:

2(x+3)+3(x-1)+13=4(x+5)+19

We move all terms to the left:

2(x+3)+3(x-1)+13-(4(x+5)+19)=0

We multiply parentheses

2x+3x-(4(x+5)+19)+6-3+13=0


We calculate terms in parentheses: -(4(x+5)+19), so:

4(x+5)+19

We multiply parentheses

4x+20+19

We add all the numbers together, and all the variables

4x+39

Back to the equation:

-(4x+39)


We add all the numbers together, and all the variables

5x-(4x+39)+16=0

We get rid of parentheses

5x-4x-39+16=0

We add all the numbers together, and all the variables

x-23=0

We move all terms containing x to the left, all other terms to the right

x=23