(x+12)(x+11)=0

Solution for (x+12)(x+11)=0 equation:

(x+12)(x+11)=0

We multiply parentheses ..

(+x^2+11x+12x+132)=0

We get rid of parentheses

x^2+11x+12x+132=0

We add all the numbers together, and all the variables

x^2+23x+132=0

a = 1; b = 23; c = +132;
Δ = b2-4ac
Δ = 232-4·1·132
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-1}{2*1}=\frac{-24}{2}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+1}{2*1}=\frac{-22}{2}
=-11
$