3(x-1)+2=6-(x+3)+4

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Solution for 3(x-1)+2=6-(x+3)+4 equation: 



3(x-1)+2=6-(x+3)+4

We move all terms to the left:

3(x-1)+2-(6-(x+3)+4)=0

We multiply parentheses

3x-(6-(x+3)+4)-3+2=0



We calculate terms in parentheses: -(6-(x+3)+4), so:

6-(x+3)+4

determiningTheFunctionDomain
-(x+3)+6+4

We add all the numbers together, and all the variables

-(x+3)+10

We get rid of parentheses

-x-3+10

We add all the numbers together, and all the variables

-1x+7

Back to the equation:

-(-1x+7)



We add all the numbers together, and all the variables

3x-(-1x+7)-1=0

We get rid of parentheses

3x+1x-7-1=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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