(2x+1)(2x+3)(x-1)(x-2)=30

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Solution for (2x+1)(2x+3)(x-1)(x-2)=30 equation: 



(2x+1)(2x+3)(x-1)(x-2)=30

We move all terms to the left:

(2x+1)(2x+3)(x-1)(x-2)-(30)=0

We multiply parentheses ..

(+4x^2+6x+2x+3)(x-1)(x-2)-30=0

We multiply parentheses ..

(+4x^2+6x+2x+3)(+x^2-2x-1x+2)-30=0

We move all terms containing x to the left, all other terms to the right

(+4x^2+6x+2x+3)(+x^2-2x-1x+2)=30

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