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(x)(x+2)=1088
We move all terms to the left:
(x)(x+2)-(1088)=0
We multiply parentheses
x^2+2x-1088=0
a = 1; b = 2; c = -1088;
Δ = b2-4ac
Δ = 22-4·1·(-1088)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-66}{2*1}=\frac{-68}{2} =-34 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+66}{2*1}=\frac{64}{2} =32 $
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