2(n-1)=4n=2(3n-1

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Solution for 2(n-1)=4n=2(3n-1 equation: 



2(n-1)=4n=2(3n-1

We move all terms to the left:

2(n-1)-(4n)=0

We add all the numbers together, and all the variables

-4n+2(n-1)=0

We multiply parentheses

-4n+2n-2=0

We add all the numbers together, and all the variables

-2n-2=0

We move all terms containing n to the left, all other terms to the right

-2n=2

n=2/-2

n=-1

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