(v+7)(8v=7)=0

Solution for (v+7)(8v=7)=0 equation:

(v+7)(8v=7)=0

We move all terms to the left:

(v+7)(8v-(7))=0

We multiply parentheses ..

(+8v^2-7v+56v-49)=0

We get rid of parentheses

8v^2-7v+56v-49=0

We add all the numbers together, and all the variables

8v^2+49v-49=0

a = 8; b = 49; c = -49;
Δ = b2-4ac
Δ = 492-4·8·(-49)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-63}{2*8}=\frac{-112}{16}
=-7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+63}{2*8}=\frac{14}{16}
=7/8
$