2(y+4)=6(2y-2)

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Solution for 2(y+4)=6(2y-2) equation: 



2(y+4)=6(2y-2)

We move all terms to the left:

2(y+4)-(6(2y-2))=0

We multiply parentheses

2y-(6(2y-2))+8=0



We calculate terms in parentheses: -(6(2y-2)), so:

6(2y-2)

We multiply parentheses

12y-12

Back to the equation:

-(12y-12)



We get rid of parentheses

2y-12y+12+8=0

We add all the numbers together, and all the variables

-10y+20=0

We move all terms containing y to the left, all other terms to the right

-10y=-20

y=-20/-10

y=+2

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