4(x-2)+10=2(x+3)+12

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Solution for 4(x-2)+10=2(x+3)+12 equation: 



4(x-2)+10=2(x+3)+12

We move all terms to the left:

4(x-2)+10-(2(x+3)+12)=0

We multiply parentheses

4x-(2(x+3)+12)-8+10=0



We calculate terms in parentheses: -(2(x+3)+12), so:

2(x+3)+12

We multiply parentheses

2x+6+12

We add all the numbers together, and all the variables

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

4x-(2x+18)+2=0

We get rid of parentheses

4x-2x-18+2=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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