(r+3)+(4r-28)=45

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Solution for (r+3)+(4r-28)=45 equation: 



(r+3)+(4r-28)=45

We move all terms to the left:

(r+3)+(4r-28)-(45)=0

We get rid of parentheses

r+4r+3-28-45=0

We add all the numbers together, and all the variables

5r-70=0

We move all terms containing r to the left, all other terms to the right

5r=70

r=70/5

r=14

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