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x+(x+35)+(x+46)+1/5x=360
We move all terms to the left:
x+(x+35)+(x+46)+1/5x-(360)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
x+x+x+1/5x+35+46-360=0
We multiply all the terms by the denominator
x*5x+x*5x+x*5x+35*5x+46*5x-360*5x+1=0
Wy multiply elements
5x^2+5x^2+5x^2+175x+230x-1800x+1=0
We add all the numbers together, and all the variables
15x^2-1395x+1=0
a = 15; b = -1395; c = +1;
Δ = b2-4ac
Δ = -13952-4·15·1
Δ = 1945965
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1395)-\sqrt{1945965}}{2*15}=\frac{1395-\sqrt{1945965}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1395)+\sqrt{1945965}}{2*15}=\frac{1395+\sqrt{1945965}}{30} $
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