7(y+2)=-2(4y-4)+5y

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Solution for 7(y+2)=-2(4y-4)+5y equation: 



7(y+2)=-2(4y-4)+5y

We move all terms to the left:

7(y+2)-(-2(4y-4)+5y)=0

We multiply parentheses

7y-(-2(4y-4)+5y)+14=0



We calculate terms in parentheses: -(-2(4y-4)+5y), so:

-2(4y-4)+5y

We add all the numbers together, and all the variables

5y-2(4y-4)

We multiply parentheses

5y-8y+8

We add all the numbers together, and all the variables

-3y+8

Back to the equation:

-(-3y+8)



We get rid of parentheses

7y+3y-8+14=0

We add all the numbers together, and all the variables

10y+6=0

We move all terms containing y to the left, all other terms to the right

10y=-6

y=-6/10

y=-3/5

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