(n-6)/3=(n-2)/2

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Solution for (n-6)/3=(n-2)/2 equation: 



(n-6)/3=(n-2)/2

We move all terms to the left:

(n-6)/3-((n-2)/2)=0

We calculate fractions


n/()+(-((n-2)*3)/()=0



We calculate terms in parentheses: +(-((n-2)*3)/(), so:

-((n-2)*3)/(

We multiply all the terms by the denominator


-((n-2)*3)



We calculate terms in parentheses: -((n-2)*3), so:

(n-2)*3

We multiply parentheses

3n-6

Back to the equation:

-(3n-6)



We get rid of parentheses

-3n+6

Back to the equation:

+(-3n+6)



We get rid of parentheses

n/()-3n+6=0

We multiply all the terms by the denominator


n-3n*()+6*()=0

We add all the numbers together, and all the variables

n-3n*()=0

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