4a+3(a-4)=2(a-2)

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Solution for 4a+3(a-4)=2(a-2) equation: 



4a+3(a-4)=2(a-2)

We move all terms to the left:

4a+3(a-4)-(2(a-2))=0

We multiply parentheses

4a+3a-(2(a-2))-12=0



We calculate terms in parentheses: -(2(a-2)), so:

2(a-2)

We multiply parentheses

2a-4

Back to the equation:

-(2a-4)



We add all the numbers together, and all the variables

7a-(2a-4)-12=0

We get rid of parentheses

7a-2a+4-12=0

We add all the numbers together, and all the variables

5a-8=0

We move all terms containing a to the left, all other terms to the right

5a=8

a=8/5

a=1+3/5

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