(4x+41)=(3x+45)

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Solution for (4x+41)=(3x+45) equation: 



(4x+41)=(3x+45)

We move all terms to the left:

(4x+41)-((3x+45))=0

We get rid of parentheses

4x-((3x+45))+41=0



We calculate terms in parentheses: -((3x+45)), so:

(3x+45)

We get rid of parentheses

3x+45

Back to the equation:

-(3x+45)



We get rid of parentheses

4x-3x-45+41=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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