(n-1)(n-2)=336

Solution for (n-1)(n-2)=336 equation:

(n-1)(n-2)=336

We move all terms to the left:

(n-1)(n-2)-(336)=0

We multiply parentheses ..

(+n^2-2n-1n+2)-336=0

We get rid of parentheses

n^2-2n-1n+2-336=0

We add all the numbers together, and all the variables

n^2-3n-334=0

a = 1; b = -3; c = -334;
Δ = b2-4ac
Δ = -32-4·1·(-334)
Δ = 1345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1345}}{2*1}=\frac{3-\sqrt{1345}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1345}}{2*1}=\frac{3+\sqrt{1345}}{2}
$