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2x(3x-18)=2x-8+3x
We move all terms to the left:
2x(3x-18)-(2x-8+3x)=0
We add all the numbers together, and all the variables
2x(3x-18)-(5x-8)=0
We multiply parentheses
6x^2-36x-(5x-8)=0
We get rid of parentheses
6x^2-36x-5x+8=0
We add all the numbers together, and all the variables
6x^2-41x+8=0
a = 6; b = -41; c = +8;
Δ = b2-4ac
Δ = -412-4·6·8
Δ = 1489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-\sqrt{1489}}{2*6}=\frac{41-\sqrt{1489}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+\sqrt{1489}}{2*6}=\frac{41+\sqrt{1489}}{12} $
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