8-3/4(x-4)=1/8(x+1)

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Solution for 8-3/4(x-4)=1/8(x+1) equation: 



8-3/4(x-4)=1/8(x+1)

We move all terms to the left:

8-3/4(x-4)-(1/8(x+1))=0



Domain of the equation: 4(x-4)!=0

x∈R





Domain of the equation: 8(x+1))!=0

x∈R



We calculate fractions


(-24xx/(4(x-4)*8(x+1)))+(-4xx/(4(x-4)*8(x+1)))+8=0



We calculate terms in parentheses: +(-24xx/(4(x-4)*8(x+1))), so:

-24xx/(4(x-4)*8(x+1))

We multiply all the terms by the denominator


-24xx

Back to the equation:

+(-24xx)





We calculate terms in parentheses: +(-4xx/(4(x-4)*8(x+1))), so:

-4xx/(4(x-4)*8(x+1))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

-24xx-4xx+8=0

We move all terms containing x to the left, all other terms to the right

-24xx-4xx=-8

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