(n+2)=9(6-n)

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Solution for (n+2)=9(6-n) equation:



(n+2)=9(6-n)
We move all terms to the left:
(n+2)-(9(6-n))=0
We add all the numbers together, and all the variables
(n+2)-(9(-1n+6))=0
We get rid of parentheses
n-(9(-1n+6))+2=0
We calculate terms in parentheses: -(9(-1n+6)), so:
9(-1n+6)
We multiply parentheses
-9n+54
Back to the equation:
-(-9n+54)
We get rid of parentheses
n+9n-54+2=0
We add all the numbers together, and all the variables
10n-52=0
We move all terms containing n to the left, all other terms to the right
10n=52
n=52/10
n=5+1/5

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