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((x-3)-3)+(2/3*x)=12
We move all terms to the left:
((x-3)-3)+(2/3*x)-(12)=0
Domain of the equation: 3*x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
((x-3)-3)+(+2/3*x)-12=0
We get rid of parentheses
((x-3)-3)+2/3*x-12=0
We multiply all the terms by the denominator
(((x-3)-3))*3*x-12*3*x+2=0
Wy multiply elements
(((x-3)-3))*3*x-36x*x+2=0
Wy multiply elements
-36x^2+(((x-3)-3))*3*x+2=0
We move all terms containing x to the left, all other terms to the right
-36x^2+(((x-3)-3))*3*x=-2
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