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18y^2-47y=0
a = 18; b = -47; c = 0;
Δ = b2-4ac
Δ = -472-4·18·0
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-47}{2*18}=\frac{0}{36} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+47}{2*18}=\frac{94}{36} =2+11/18 $
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