(m-1.8)(m+1.8)m=1.7

Solution for (m-1.8)(m+1.8)m=1.7 equation:

(m-1.8)(m+1.8)m=1.7

We move all terms to the left:

(m-1.8)(m+1.8)m-(1.7)=0

We add all the numbers together, and all the variables

(m-1.8)(m+1.8)m-1.7=0

We use the square of the difference formula

m^2-3.24-1.7=0

We add all the numbers together, and all the variables

m^2-4.94=0

a = 1; b = 0; c = -4.94;
Δ = b2-4ac
Δ = 02-4·1·(-4.94)
Δ = 19.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{19.76}}{2*1}=\frac{0-\sqrt{19.76}}{2}
=-\frac{\sqrt{}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{19.76}}{2*1}=\frac{0+\sqrt{19.76}}{2}
=\frac{\sqrt{}}{2}
$