5(2x-3)=6(x+2)-1

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Solution for 5(2x-3)=6(x+2)-1 equation: 



5(2x-3)=6(x+2)-1

We move all terms to the left:

5(2x-3)-(6(x+2)-1)=0

We multiply parentheses

10x-(6(x+2)-1)-15=0



We calculate terms in parentheses: -(6(x+2)-1), so:

6(x+2)-1

We multiply parentheses

6x+12-1

We add all the numbers together, and all the variables

6x+11

Back to the equation:

-(6x+11)



We get rid of parentheses

10x-6x-11-15=0

We add all the numbers together, and all the variables

4x-26=0

We move all terms containing x to the left, all other terms to the right

4x=26

x=26/4

x=6+1/2

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