-3x2+66x=0

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Solution for -3x2+66x=0 equation:



-3x^2+66x=0
a = -3; b = 66; c = 0;
Δ = b2-4ac
Δ = 662-4·(-3)·0
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-66}{2*-3}=\frac{-132}{-6} =+22 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+66}{2*-3}=\frac{0}{-6} =0 $

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