(log3x)^2-1/2log3x=3/2

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Solution for (log3x)^2-1/2log3x=3/2 equation: 


x^3-(2*x^2)+x-2 = 0

1*x^3-(2.95*x^2)+0*x+0 = 0

1*x^3-(2*x^2)+6*x-12 = 0

(x^2-4)/(x-2) = 1

cos(3*x)*ln(5*x)

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