ln((x-2)+(2x+1))=5

Solution for ln((x-2)+(2x+1))=5 equation:

Simplifying
ln((x + -2) + (2x + 1)) = 5

Reorder the terms:
ln((-2 + x) + (2x + 1)) = 5

Remove parenthesis around (-2 + x)
ln(-2 + x + (2x + 1)) = 5

Reorder the terms:
ln(-2 + x + (1 + 2x)) = 5

Remove parenthesis around (1 + 2x)
ln(-2 + x + 1 + 2x) = 5

Reorder the terms:
ln(-2 + 1 + x + 2x) = 5

Combine like terms: -2 + 1 = -1
ln(-1 + x + 2x) = 5

Combine like terms: x + 2x = 3x
ln(-1 + 3x) = 5
(-1 * ln + 3x * ln) = 5
(-1ln + 3lnx) = 5

Solving
-1ln + 3lnx = 5

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-5 + -1ln + 3lnx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -1ln + 3lnx = 0

The solution to this equation could not be determined.