((2x-6)/2)-x=3

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Solution for ((2x-6)/2)-x=3 equation: 


x in (-oo:+oo)

(2*x-6)/2-x = 3 // - 3

(2*x-6)/2-x-3 = 0

(2*x-6)/2+(2*(-x))/2+(-3*2)/2 = 0

2*x+2*(-x)-3*2-6 = 0

-6-6 = 0

-12 = 0

-12/2 = 0

-12/2 = 0 // * 2

-12 = 0

-12 = 0

x belongs to the empty set

x belongs to the empty set

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