(g-4)+2(g+10)=7(g-3)-11g-13

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Solution for (g-4)+2(g+10)=7(g-3)-11g-13 equation: 



(g-4)+2(g+10)=7(g-3)-11g-13

We move all terms to the left:

(g-4)+2(g+10)-(7(g-3)-11g-13)=0

We multiply parentheses

(g-4)+2g-(7(g-3)-11g-13)+20=0

We get rid of parentheses

g+2g-(7(g-3)-11g-13)-4+20=0



We calculate terms in parentheses: -(7(g-3)-11g-13), so:

7(g-3)-11g-13

We add all the numbers together, and all the variables

-11g+7(g-3)-13

We multiply parentheses

-11g+7g-21-13

We add all the numbers together, and all the variables

-4g-34

Back to the equation:

-(-4g-34)



We add all the numbers together, and all the variables

3g-(-4g-34)+16=0

We get rid of parentheses

3g+4g+34+16=0

We add all the numbers together, and all the variables

7g+50=0

We move all terms containing g to the left, all other terms to the right

7g=-50

g=-50/7

g=-7+1/7

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