4a+-5(a-2)=11a-4a+20

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Solution for 4a+-5(a-2)=11a-4a+20 equation: 



4a+-5(a-2)=11a-4a+20

We move all terms to the left:

4a+-5(a-2)-(11a-4a+20)=0

We add all the numbers together, and all the variables

4a-5(a-2)-(7a+20)+=0

We add all the numbers together, and all the variables

4a-5(a-2)-(7a+20)=0

We multiply parentheses

4a-5a-(7a+20)+10=0

We get rid of parentheses

4a-5a-7a-20+10=0

We add all the numbers together, and all the variables

-8a-10=0

We move all terms containing a to the left, all other terms to the right

-8a=10

a=10/-8

a=-1+1/4

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