(b-10)(b=10)

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Solution for (b-10)(b=10) equation: 



(b-10)(b=10)

We move all terms to the left:

(b-10)(b-(10))=0

We multiply parentheses ..

(+b^2-10b-10b+100)=0

We get rid of parentheses

b^2-10b-10b+100=0

We add all the numbers together, and all the variables

b^2-20b+100=0

a = 1; b = -20; c = +100;
Δ = b2-4ac
Δ = -202-4·1·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{20}{2}=10$

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